Updated simulink model with real experimental data

This commit is contained in:
Radu C. Martin 2021-03-11 13:22:40 +01:00
parent 99b31a6fa7
commit 60b2b2b3df
2 changed files with 53 additions and 4 deletions

View file

@ -3,11 +3,26 @@ close all
clc clc
%%%%%%%%%%%%%%%%%%%%%%% %%%%%%%%%%%%%%%%%%%%%%%
%% Load the experimental data
Exp1 = load("../Data/Luca_experimental_data/Exp1.mat");
py_Exp1 = load("../Data/Exp1_WDB.mat");
tin = py_Exp1.Exp1_WDB(:,1);
% The power trick: when the setpoint is larger than the actual temperature
% the HVAC system is heating the room, otherwise it is cooling the room
Setpoint = Exp1.Exp1.Setpoint.values;
InsideTemp = mean([Exp1.Exp1.InsideTemp.values, Exp1.Exp1.LakeTemp.values], 2);
OutsideTemp = Exp1.Exp1.OutsideTemp.values;
HVAC_COP = 4.5;
Heating_coeff = sign(Setpoint - InsideTemp);
Heating_coeff(Heating_coeff == -1) = -1 * HVAC_COP;
%% Set the model parameters %% Set the model parameters
% Large side windows % Large side windows
window_size = [2.5 25]; window_size = [2 25];
window_roof_size = [5 5]; window_roof_size = [5 5];
surface_part = 0.1; surface_part = 0.1;
U = 1.8; % heat transfer coefficient [W/m2K] U = 1.8; % heat transfer coefficient [W/m2K]
@ -37,8 +52,42 @@ layer_density = [540 40 2240];
%% Set the run parameters %% Set the run parameters
air_exchange_rate = 2.0; air_exchange_rate = tin;
power = 0; air_exchange_rate(:,2) = 2.0;
t0 = 24;
power = [tin Heating_coeff .* (Exp1.Exp1.Power.values - 1.67 * 1000)];
Te = 60*60*24*365; Te = 60*60*24*365;
sim("polydome_model_1")
%% Run the simulation
% Note: The simlulink model loads the data separately, includes the
% calculated solar position and radiations from pvlib
simout = sim("polydome_model_1");
%% Compare the simulation results with the measured values
SimulatedTemp = simout.SimulatedTemp.Data;
figure; hold on; grid minor;
plot(tin, InsideTemp);
plot(tin, OutsideTemp);
plot(simout.tout, SimulatedTemp, 'LineWidth', 2);
plot(tin, Setpoint);
legend('InsideTemp', 'OutsideTemp', 'SimulatedTemp', 'Setpoint');
hold off;
% calculation notes for furniture wall parameters
% surface:
% 1/4 * 1.8 [m2/m2 of floor space] * 625 m2 surface = 140 m2
% 140 m2 = [7 20] m [height width]
% mass:
% 1/4 * 40 [kg/m2 of floor space] * 625 m2 surface = 6250 kg
% volume:
% 6250[kg]/600[kg/m3] = 10.41 [m3]
% thickness:
%10.41[m3]/140[m2] = 0.075m = 7.5cm

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